Chemistry, asked by Anonymous, 1 month ago

Find time when boy catches the girl or when they are at their closest separation..
velocity of boy is 50m/s and velocity of girl is 30m/s and acceleration of boy is 1m/s² and acceleration of girl is 2m/s² and distance between them is 150m​.

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Answers

Answered by mohammadsarim309
3

KGiven Final velocity (v) = 50 m/s

Initial velocity (u) = 30 m/s

Acceleration (a) = 2.5 m/s

2

We know v = u + at

∴ 50 = 30 + 2.5 t

⇒ 50 - 30 = 2.5 t

2.5

20

= t or 8 = t

∴ Time taken to accelerate = 8 seconds

Answered by brainlyLegend309
7

Answer:

Given Final velocity (v) = 50 m/s

Initial velocity (u) = 30 m/s

Acceleration (a) = 2.5 m/s

2

We know v = u + at

∴ 50 = 30 + 2.5 t

⇒ 50 - 30 = 2.5 t

2.5

20

= t or 8 = t

∴ Time taken to accelerate = 8 seconds

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