Find time when boy catches the girl or when they are at their closest separation..
velocity of boy is 50m/s and velocity of girl is 30m/s and acceleration of boy is 1m/s² and acceleration of girl is 2m/s² and distance between them is 150m.
━━━━━━━━━━━━━━━
Note : Step by step Explanation required! Don't skip any single step!
▪️Spam answer will be reported.
▪️Best answer will be marked as brainliest.
▪️ Don't Be greedy for Points.
All the best! :)
Answers
Answered by
3
KGiven Final velocity (v) = 50 m/s
Initial velocity (u) = 30 m/s
Acceleration (a) = 2.5 m/s
2
We know v = u + at
∴ 50 = 30 + 2.5 t
⇒ 50 - 30 = 2.5 t
⇒
2.5
20
= t or 8 = t
∴ Time taken to accelerate = 8 seconds
Answered by
7
Answer:
Given Final velocity (v) = 50 m/s
Initial velocity (u) = 30 m/s
Acceleration (a) = 2.5 m/s
2
We know v = u + at
∴ 50 = 30 + 2.5 t
⇒ 50 - 30 = 2.5 t
⇒
2.5
20
= t or 8 = t
∴ Time taken to accelerate = 8 seconds
Similar questions
Computer Science,
1 month ago
Math,
1 month ago
Environmental Sciences,
4 months ago
Math,
10 months ago
English,
10 months ago
Hindi,
10 months ago