Question

Find Time when P = Rs. 12000, R = 20 %, S.I. = Rs.4800​

Answer 1

Answer :-

Given :-

• Principal = Rs. 12000
• Rate of interest = 20% p.a.
• Simple interest = Rs. 4800

To Find :-

• Time

Solution :-

We know that,

Simple interest = P × R × T / 100

Substituting the value in formula and calculating the value of time :-

→ 4800 = 12000 × 20 × T / 100

→ 4800 = 120 × 20 × T

→ 4800 = 2400 × T

→ T = 4800 / 2400

→ T = 2

Time = 2 years

Answer 2

Answer:

Given :-

• Principal = ₹ 12000
• Rate = 20 %
• Simple Interest = ₹ 4800

To Find :-

Time

Solution :-

According to the question

We know that

$\begin{gathered}\quad{\underline{\boxed{\mathcal{\pmb{\quad Time \: = \: \dfrac{SI \times 100}{P \times R} \quad}}}}}\\\end{gathered}$

T = Time

SI = Simple Interest

P = Principal

R = Rate

T = 4800 × 100/12000 × 20

T = 480000/240000

T = 48/24

T = 2

$\therefore {\textsf{ \textbf{ \underline{Time is 2 years.}}}}$