Question

find tje quadratic polynomial whose zeroes are 2 and -6​

Answer 1

Step-by-step explanation:

⇒ Given zeros are α=2 and β=−6.

⇒ Sum of zeros =α+β=2+(−6)=−4

⇒ Product of zeros =α×β=2×(−6)=−12

⇒ Quadratic polynomial =x^2 −(α+β)x+(α×β)

⇒ Quadratic polynomial =x ^2−(−4)x+(−12)

∴ Quadratic polynomial =x^2 +4x−12

Answer 2

ANSWER.

• The quadratic polynomial will be –

SOLUTION.

Given zeros – 2 and -6.

→ Sum of zeros = 2 + (-6) = -4

→ Product of zeros = 2 × (-6) = -12

So, the quadratic polynomial will be,

= x² - (sum of zeros)x + (product of zeros)

= x² - (-4)x + (-12)

= x² + 4x - 12

VERIFICATION.

Given zeros = 2 and -6

Put x = 2, we get,

= (2)² + 4 × 2 - 12

= 4 + 8 - 12

= 0

Put x = -6, we get,

= (-6)² + 4 × (-6) - 12

= 36 - 24 - 12

= 0

So, our answer is correct (Verified)