Find tje ratio in which the linesegment joining the points a(3,-6) b (5,3) is divided by x axis
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Let the ratio be k:1
Now
(m1x2+m2x1)/m1+m2 = X
(m1y2+m2y1)/m1+m2 = Y. ------1eq
(Y will be 0 as the line is meeting at x axis.
using 1 eq.
(3k-6)/(k+1)=0
3k-6=0
3k=6
k=2
Ratio will be 2:1
Now
(m1x2+m2x1)/m1+m2 = X
(m1y2+m2y1)/m1+m2 = Y. ------1eq
(Y will be 0 as the line is meeting at x axis.
using 1 eq.
(3k-6)/(k+1)=0
3k-6=0
3k=6
k=2
Ratio will be 2:1
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