Question

find tje roots of the equation 2/x^2-5/x=0 x not equal to 0​

Answer 1

Answer:

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Answer 2

Answer:We think you wrote:

x^2-x-5=0

This deals with quadratic equation

Step-by-step explanation:The first term is,  x2  its coefficient is  1 .

The middle term is,  -x  its coefficient is  -1 .

The last term, "the constant", is  -5  

Step-1 : Multiply the coefficient of the first term by the constant   1 • -5 = -5  

Step-2 : Find two factors of  -5  whose sum equals the coefficient of the middle term, which is   -1 .

     -5    +    1    =    -4  

     -1    +    5    =    2

x =(1-√21)/2=-1.791

Two solutions were found :(1)x =(1-√21)/2=-1.791

( 2)x =(1+√21)/2= 2.791