Question

find tn and hence t15 of the A.P. is 3,8,13,18,.........​

Answer 1

Step-by-step explanation:

First term,a=3

common difference,d=5

tn=a+(n-1)d

=3+(n-1)5

=3+5n-5

=5n-2

t15=a+(n-1)d

=3+(15-1)5

=3+14×5

=3+70

=73

Hence value of tn is 5n-2, and value of t15 is 73...

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Answer 2

—>

The given A.P is 3,8,13,18...

here,

a = 3 , d = 8-3 = 5

tn = a+(n-1) d

tn =3+(n-1) 5

tn =5n-2

tn=a+(n-1)d

t15=3+(15-1)5

t15 = 3+14×5

t15= 3+70

t15 = 73

ans . hence value of tn is 5n-2 and value of t15 is 73