Question

Find tn for following Ap and then find 30th term of AP. 3,8,13,18​

Answer 1

Answer:

a= 3

d= a2 - a1 = 8 - 3 = 5

a3 - a2 = 13 - 8 = 5

d = 5

Tn = a + ( n - 1 )d

= 3 + (n - 1 )5

= 3 + 5n - 5

= 5n - 2

now,

the 30 th term of AP

a = 3

d = 5

n = 30 ( number of terms that is 30 )

a + ( n - 1 )d

3 + ( 30 - 1 ) 5

3 + 29 × 5

3 + 145

148

Thus, 30th term of Ap is 148