find tn for the following A.P
4,14/3,16/3,6,.......
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D=2/3 t n =a+(n-1)d 2n-10/3.
From survey the grouping it is an Arithmetic Progression where the main term (an) is 3 and the Common Difference (d) is 3.
The condition for the nth term is a + (n-1)d.
We can locate the fourth term as 3 + (4– 1)*3 = 3 + 9 = 12. Demonstrated.
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