find tne sum of finite series 1+6+11+16........96
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Answer:
answer is 1060
Step-by-step explanation:
First here we will find out the value of n
An=a+(n-1)d
96=1+ (n-1)×5
95÷5 = n-1
19=n-1
n=20
now we will find the sum
Sn=n÷2 (2a+n-1d)
Sn =20÷2 (2+19×5)
Sn=10 (106)
Sn=1060
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