Question

find to consecutive even number such that smaller of the two numbers is 8/9 times of the larger number.......
with solution​

Answer 1

Answer:

Let the two consecutive even number x-2& x

Let the two consecutive even number x-2& xgiven

Let the two consecutive even number x-2& xgivenx-2= 4/5(x)

Let the two consecutive even number x-2& xgivenx-2= 4/5(x)x-4x/5= 2

Let the two consecutive even number x-2& xgivenx-2= 4/5(x)x-4x/5= 2x/5= 2

Let the two consecutive even number x-2& xgivenx-2= 4/5(x)x-4x/5= 2x/5= 2x=10

where as smaller number is x-2= 10-2=8

Step-by-step explanation:

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Answer 2

Answer:

Refer Attachment Above please