Question

Find to consecutive positive integers sum of whose squares is 365

Answer 1

Let smaller no be x

Other no becomes x+1

ATQ

x^2+ (x+1)^2=365

2x^2 +2x+1=365

2x^2 +2x-364=0

x^2 +x-182=0

x^2 +14x-13x -182=0

Solving for x

We get  

x= 13,-14

Therefore the nos are 13,14 and -13,-14

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