Physics, asked by vikash9044, 11 months ago

Find torque............

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Answers

Answered by Steph0303
8

Solution:

Torque is defined as the cross product of Vector R and Force F, where vector R represents the distance from Axis of rotation to point of application of force.

In terms of Formula, we can write it as:

→ τ = r × F

→ τ = r.F.SinФ

where, Ф is the angle between F and r vectors.

According to the question, we are given that,

→ Magnitude of Force (F) = 50 N

→ Distance from Axis (r) = 3 m

Rearranging the vectors, we get the angle between them to be 70°

Therefore substituting in the formula. we get:

→ τ = 50 × 3 × Sin 70°

According to trigonometric identity,

→ SinФ = Cos( 90 - Ф)

→ Sin 70 = Cos ( 90 - 70 ) = Cos 20

Therefore Sin 70 = Cos 20 = 0.9  [Given]

Hence Torque is calculated as;

→ τ = 50 × 3 × 0.9

→ τ = 135 N.m

Hence the torque applied by the boy along the axis is 135 N.m

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