Find torque............
Answers
Solution:
Torque is defined as the cross product of Vector R and Force F, where vector R represents the distance from Axis of rotation to point of application of force.
In terms of Formula, we can write it as:
→ τ = r × F
→ τ = r.F.SinФ
where, Ф is the angle between F and r vectors.
According to the question, we are given that,
→ Magnitude of Force (F) = 50 N
→ Distance from Axis (r) = 3 m
Rearranging the vectors, we get the angle between them to be 70°
Therefore substituting in the formula. we get:
→ τ = 50 × 3 × Sin 70°
According to trigonometric identity,
→ SinФ = Cos( 90 - Ф)
→ Sin 70 = Cos ( 90 - 70 ) = Cos 20
Therefore Sin 70 = Cos 20 = 0.9 [Given]
Hence Torque is calculated as;
→ τ = 50 × 3 × 0.9
→ τ = 135 N.m
Hence the torque applied by the boy along the axis is 135 N.m