Question

find total effective resistances ​

Answer 1

$\huge\mathfrak{solution}$

Given:

• In the given figure , All the resistances are in series combination:

To find:

• Total equivalent resistance=?

Answer:

• Let

•r1 = 6Ω

•r2=2Ω

•r3=5Ω

As we know that:

In series combination :

we find equivalent resistance by :

•R(eq)= r1 +r2 + r3...

=> R(eq)= (6+2+5)Ω

=> R(eq)= 13 Ω

Hence, The total effective/equivalent resistance is 13Ω.

Answer 2

$\large{\red{\underline{\textsf{Given-}}}}$

→ 3 resistors connected in series.

R1 = $\sf 6 \Omega$

R2 = $\sf 2 \Omega$

R3 = $\sf 5 \Omega$

$\large{\red{\underline{\textsf{To\:Find-}}}}$

→ Total effective resistances

$\Large{\red{\underline{\textsf{Solution}}}}$

♦ The total effective resistances , connected in series is given by -

R' = R1 + R2 + R3

R' = $\sf 6 \Omega$ $\sf 2 \Omega$ $\sf 5 \Omega$

R' = $\sf 13 \Omega$

$\Huge{\red{\underline{\textsf{R'=\sf 13 \Omega }}}}$

$\rule{200}2$