Math, asked by maxsteelgo79, 16 days ago

Find total K.E for a 2 kg ring rolling on the table with a linear speed of 4 m/s.

Answers

Answered by 9102385222skp

1

Answer:

K.E.=1/2mv²

1/2×2×4×4

16 joule .ans

Attachments:

Answered by umer556601

0

Answer:

16

Step-by-step explanation:

K. E=1/2mv²

=1/2x2000x16

=1000x16

=16000

=16kj

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