Find total negative charge on 2 g of H2
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Explanation:
A water molecule (H
2
O) contain no. of proton (np)=8+2×1=10 and so no. of electrons =20
Electroneutrating principle statter state
net positive charge = net negative charge
As L cup of water holder 250 g water,
no. of moles =
molar mass
given mass
=
18
250
=
9
125
moles
1 mol of water contains N
A
no. of molecular
⇒ Total no. of molecular =
9
125
×6.02×10
24
=8.361×10
24
so, net positive charge present =20×8.361×10
24
×1.6×10
−19
(charge of photon)
⇒ Q=2.68×10
7
C
Thus, net negative charges presents =−Q
=−2.68×10
7
C
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