Question

Find total number of molecules, atoms and ions present in 234 g of sodium chloride. And also find the total number of electrons, protons and neutrons present in 23 g of Sodium element. Take (Na-23 and Cl=35.5).

Please Fast and with explanation ​

Answer 1

Explanation:

14.5g of NaCl is equal to 0.248 mol according to the equation

n=mM

No,

this equates to 1.495×1023 Sodium chloride molecules.

We get this if we multiply 0.248 mol with Avogadro's number, 6.022×1023

Each molecule of Sodium chroride holds two atomic ions bonded in an ionic bond- Na+ and Cl− in a 1:1 ratio. This means that the amount of molecules correspond with each of the individual ions.

So :

Number of Sodium ions=Number of Chloride ions= 1.495×1023 ions

So the total amount of ions is twice this number, 2.990×1023 ions in total.