find total resistance in this circuit diagram.
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1
Explanation:
5ohm and 3ohm are in series combination so total resistance is 8ohm
smiliary 7ohm nd 5ohm is in series combination so total resistance is 12ohm
8ohm 10 ohm and 12ohm is in parallel combination so total resistance is
(8x10x12)/(8+10+12)= 32ohm
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0
Answer:
15Ω
Explanation:
STEP 1:
as R1 and R2 is in series so Re = R1+R2 = 3Ω+7Ω = 10Ω
STEP 2:
here Re and R3 are in parallel so 1/eq(equivalent resistence)= (1/10+1/10)=1/5
i.e eq = 5Ω
STEP 3:
here eq, R4 and R5 are in series so total resistence = eq+r4+r5=5Ω+5Ω+5Ω=15Ω
hence, the total resistence in circuit is 15Ω.
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