Find total surface area of a hallow globe with radius 18 cm and thickness 10mm
Answers
Answered by
2
Answer:
Total surface area of hollow sphere = 4πr12 + 4πr22
Where, r1 = radius of outer surface
r2 = radius of inner surface
Here, r1 = 18 cm, thickness = 10 mm = 1 cm
⇒ r2 = 17 cm
∴ Total surface area = [4 × (182 + 172)] π = 2452 π
Hence solved ✅✅✅
Thanks for asking...
Similar questions