Math, asked by sanjaykadari, 4 months ago

Find total surface area of the following cylinders​

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Answers

Answered by 100lnkiminki
1

mAnswer:

TSA=2 ×22/7×14(14+8)

=2×44(22)

=88×22m

=1936m

I HOPE MY ANSWER HELPS YOU

Answered by Intelligentcat
12

Answer:

For Figure 1

\setlength{\unitlength}{1mm}\begin{picture}(5,5)\thicklines\multiput(-0.5,-1)(26,0){2}{\line(0,1){40}}\multiput(12.5,-1)(0,3.2){13}{\line(0,1){1.6}}\multiput(12.5,-1)(0,40){2}{\multiput(0,0)(2,0){7}{\line(1,0){1}}}\multiput(0,0)(0,40){2}{\qbezier(1,0)(12,3)(24,0)\qbezier(1,0)(-2,-1)(1,-2)\qbezier(24,0)(27,-1)(24,-2)\qbezier(1,-2)(12,-5)(24,-2)}\multiput(18,2)(0,32){2}{\sf{14}}\put(9,17.5){\sf{8}}\end{picture}

We know the T.S.A of cylinder

Total Surface Area of Cylinder = 2πr( r + h )

  • Radius = 14 cm
  • Height = 8 cm

Substituting the values in the formula :-

↬ 2 × 22/7 × 14 ( 14 + 8 )

↬ 2 × 22 × 2 ( 22)

↬ 44 × 44

1936 cm²

For figure 2 :-

\setlength{\unitlength}{1mm}\begin{picture}(5,5)\thicklines\multiput(-0.5,-1)(26,0){2}{\line(0,1){40}}\multiput(12.5,-1)(0,3.2){13}{\line(0,1){1.6}}\multiput(12.5,-1)(0,40){2}{\multiput(0,0)(2,0){7}{\line(1,0){1}}}\multiput(0,0)(0,40){2}{\qbezier(1,0)(12,3)(24,0)\qbezier(1,0)(-2,-1)(1,-2)\qbezier(24,0)(27,-1)(24,-2)\qbezier(1,-2)(12,-5)(24,-2)}\multiput(18,2)(0,32){2}{\sf{2}}\put(9,17.5){\sf{2}}\end{picture}

Total Surface Area of Cylinder = 2πr( r + h )

  • Radius = 2m
  • Height = 2m

Substituting the values in the formula :-

↬ 2 × 22/7 × 2 ( 2 + 2)

↬ 2 × 22/7 × 2 ( 4)

↬ 44/7 × 8

50.24 m²

_____________________________

\boxed{\begin{minipage}{6.2 cm}\bigstar$\:\underline{\textbf{Formulae Related to Cylinder :}}\\\\\sf {\textcircled{\footnotesize\textsf{1}}} \:Area\:of\:Base\:and\:top =\pi r^2 \\\\ \sf {\textcircled{\footnotesize\textsf{2}}} \:\:Curved \: Surface \: Area =2 \pi rh\\\\\sf{\textcircled{\footnotesize\textsf{3}}} \:\:Total \: Surface \: Area = 2 \pi r(h + r)\\ \\{\textcircled{\footnotesize\textsf{4}}} \: \:Volume=\pi r^2h\end{minipage}}

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