Math, asked by vanshika6149, 1 month ago

Find trigonometric function of angles 180 and 270 degree

Answers

Answered by mathdude500
4

\large\underline{\sf{Solution-}}

 \red{\rm :\longmapsto\:sin(180\degree  - x) = sinx}

 \red{\rm :\longmapsto\:cos(180\degree  - x) =  -  \: cosx}

 \red{\rm :\longmapsto\:tan(180\degree  - x) =  -  \: tanx}

 \red{\rm :\longmapsto\:cosec(180\degree  - x) =  \: cosecx}

 \red{\rm :\longmapsto\:sec(180\degree  - x) = -   \: secx}

 \red{\rm :\longmapsto\:cot(180\degree  - x) = -   \: cotx}

 \green{\rm :\longmapsto\:sin(180\degree  + x) =  - sinx}

 \green{\rm :\longmapsto\:cos(180\degree  + x) =  - cosx}

 \green{\rm :\longmapsto\:tan(180\degree  + x) =  tanx}

 \green{\rm :\longmapsto\:cosec(180\degree  + x) =  - cosecx}

 \green{\rm :\longmapsto\:sec(180\degree  + x) =  - secx}

 \green{\rm :\longmapsto\:cot(180\degree  + x) =  cotx}

 \blue{\rm :\longmapsto\:sin(270\degree  - x) =  - cosx}

 \blue{\rm :\longmapsto\:cos(270\degree  - x) =  - sinx}

 \blue{\rm :\longmapsto\:tan(270\degree  - x) = cotx}

 \blue{\rm :\longmapsto\:cosec(270\degree  - x) = -  secx}

 \blue{\rm :\longmapsto\:sec(270\degree  - x) = -  cosecx}

 \blue{\rm :\longmapsto\:cot(270\degree  - x) =   tanx}

 \purple{\rm :\longmapsto\:sin(270\degree  + x) =  - cosx}

 \purple{\rm :\longmapsto\:cos(270\degree  + x) =   sinx}

 \purple{\rm :\longmapsto\:tan(270\degree  + x) =    - cotx}

 \purple{\rm :\longmapsto\:cosec(270\degree  + x) =    - secx}

 \purple{\rm :\longmapsto\:sec(270\degree  + x) =  cosecx}

 \purple{\rm :\longmapsto\:cot(270\degree  + x) =   - tanx}

Answered by XxitsmrseenuxX
21

Answer:

\large\underline{\sf{Solution-}}

 \red{\rm :\longmapsto\:sin(180\degree  - x) = sinx}

 \red{\rm :\longmapsto\:cos(180\degree  - x) =  -  \: cosx}

 \red{\rm :\longmapsto\:tan(180\degree  - x) =  -  \: tanx}

 \red{\rm :\longmapsto\:cosec(180\degree  - x) =  \: cosecx}

 \red{\rm :\longmapsto\:sec(180\degree  - x) = -   \: secx}

 \red{\rm :\longmapsto\:cot(180\degree  - x) = -   \: cotx}

 \green{\rm :\longmapsto\:sin(180\degree  + x) =  - sinx}

 \green{\rm :\longmapsto\:cos(180\degree  + x) =  - cosx}

 \green{\rm :\longmapsto\:tan(180\degree  + x) =  tanx}

 \green{\rm :\longmapsto\:cosec(180\degree  + x) =  - cosecx}

 \green{\rm :\longmapsto\:sec(180\degree  + x) =  - secx}

 \green{\rm :\longmapsto\:cot(180\degree  + x) =  cotx}

 \blue{\rm :\longmapsto\:sin(270\degree  - x) =  - cosx}

 \blue{\rm :\longmapsto\:cos(270\degree  - x) =  - sinx}

 \blue{\rm :\longmapsto\:tan(270\degree  - x) = cotx}

 \blue{\rm :\longmapsto\:cosec(270\degree  - x) = -  secx}

 \blue{\rm :\longmapsto\:sec(270\degree  - x) = -  cosecx}

 \blue{\rm :\longmapsto\:cot(270\degree  - x) =   tanx}

 \purple{\rm :\longmapsto\:sin(270\degree  + x) =  - cosx}

 \purple{\rm :\longmapsto\:cos(270\degree  + x) =   sinx}

 \purple{\rm :\longmapsto\:tan(270\degree  + x) =    - cotx}

 \purple{\rm :\longmapsto\:cosec(270\degree  + x) =    - secx}

 \purple{\rm :\longmapsto\:sec(270\degree  + x) =  cosecx}

 \purple{\rm :\longmapsto\:cot(270\degree  + x) =   - tanx}

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