Find TRS......................................
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Let angles P , Q , R be 3x , 2x and xd respectively.
By Angle Sum Property of a Triangle , We have
3x+2x+x = 180°
6x = 180°
x = 30°
Angle P = 3 *30°=90°
Angle Q =2*30°=60°
Angle R = 30°
Now ,
Angle PRS = Angle P + Angle Q
=90°+ 60° = 150°
Now ,
Angle PRQ + PRT+TRS = 180°(Linear Pair)
= 30°+90°+Angle TRS = 180°
Angle TRS = 180° - 120° = 60°
So , Angle TRS = 60°
By Angle Sum Property of a Triangle , We have
3x+2x+x = 180°
6x = 180°
x = 30°
Angle P = 3 *30°=90°
Angle Q =2*30°=60°
Angle R = 30°
Now ,
Angle PRS = Angle P + Angle Q
=90°+ 60° = 150°
Now ,
Angle PRQ + PRT+TRS = 180°(Linear Pair)
= 30°+90°+Angle TRS = 180°
Angle TRS = 180° - 120° = 60°
So , Angle TRS = 60°
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