Question

find tthe number of the sides in a polygon if the sum of its interior angle is:
(i). 900 (ii). 1620 (iii). 16 right angle​

Answer 1

Answer:

1) let the number of sides be X

sum of all interior angle=(2x-4)*90

=900=(2x-4)*90

=900/90=2x-4

=10=2x-4

=10+4=2x

=14=2x

=7=x

2) let the number of sides be X

sum of all interior angle=(2x-4)*90

=1620=(2x-4)*90

=1620/90=2x-4

=18=2x-4

=18+4=2x

=22=2x

=11=x

3)16 right angles=16*90=1440

sum of all interior angle=(2x-4)*90

=1440=(2x-4)*90

=1440/90=2x-4

=16=2x-4

=16+4=2x

=20=2x

=10=x

mark this as brainliest please