find tue nth term if the sum of n term of an ap is 2n(2) + 5n
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Sum of n terms = 2n²+5n
Now to find nth term subtract Sn+1 and Sn
Sn+1=2(n+1)²+5(n+1)
=2(n²+1+2n)+5n+5
=2n²+2+9n+5
=2n²+9n+7
Now
Sn=2n²+5n
nth term = Sn+1 - Sn
=2n²+9n+7-2n²-5n
=4n+7
hope it helps.
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