Question

Find two complex numbers whose sum is 4
an product is 8​

Answer 1

Answer:

here is your answers,,,,,

Answer 2

Answer: z1= 2+2i and z2= 2-2i

Step-by-step explanation:

Consider two complex numbers, z1= a+bi and z2= a-bi

Now according to the question,

z1+z2=4

Therefore, (a+bi)+(a-bi)=4

                   a+a+bi-bi=4... (Opening brackets)

                   2a=4

                    a=2, this is equation(1)

Also,

z1*z2=8

Therefore, (a+bi)(a-bi)=8

                   (a)^2 - (bi)^2=8... [since (a+b)(a-b)=a^2 - b^2]

                   (2)^2 - b^2(-1)=8... (i^2= -1)

                   4+b^2=8

                   b^2=4

                   b=2, this is equation(2)

Now substitute the values of a and b back to z1 and z2

Therefore, z1=2+2i and z2=2-2i