Question

find two consecutive add positive integers, sum of whose Square is 290​

Answer 1

Answer:

let the two odd consecutive integer be x and x+2

Answer 2

let one odd positive integer be (x+1) so another one becomes (x+3)

now it is given that

(x+1)^2 + (x+3)^2 = 290

x^2 + 1 + 2x + x^2 + 9 + 6x = 290

2x^2 + 8x + 10 = 290

2x^2 + 8x = 280

OR 2x^2 +8x - 280 = 0

on dividing the equation by 2 we get

x^2 + 4x - 140 = 0

On solving this equation we will get 2 values of x.

i.e. +10 and -12

Since positive is given so put the positive value of x and find the numbers

1. 11
2. 13

these are the numbers