Question

find two consecutive even integers such that 3 times the first added to twice the second gives 64​

Answer 1

Answer:

let one no. be (2x)

and the other is (2x+2)

now,

ATQ=>

3(2x)+2(2x+2) =64

6x + 4x+4=64

10x=64-4

10x=60

x=60/10

x=6

therefore, the two no.s are 2x=2*6=12

and 2nd =2(6)+2=14

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