Question

Find two consecutive even integers such that twice the smaller exceeds the larger is by 18​

Answer 1

Answer:

-18 and -17 are the number.

Step-by-step explanation:

2X=X-18

Answer 2

$\mathfrak{\large{\underline{\underline{Answer :-}}}}$

The Consecutive Even numbers are 20 and 22.

$\mathfrak{\large{\underline{\underline{Explanation :-}}}}$

Given :

The Numbers are consecutive even integers

Twice of the Smaller number exceeds the larger is by 18

To Find :

The Numbers

Solution :

Consecutive numbers are the numbers which follow each other continuously.

Consider the Consecutive numbers as -

• Smaller as x
• Larger as (x + 2)

According to the Question -

Twice of the Smaller number exceeds the larger is by 18

★ $\boxed{\sf{2x=(x+2)+18}}$

$\longrightarrow$ 2x = (x + 2) + 18

$\longrightarrow$ 2x = x + 2 + 18

$\longrightarrow$ 2x = x + 20

$\longrightarrow$ 2x - x = 20

$\longrightarrow$ x = 20

Smaller Number = 20

$\rule{300}{1.5}$

★ Value of (x + 2)

$\longrightarrow$ 20 + 2

$\longrightarrow$ 22

Larger Number = 22

$\therefore$ The Consecutive Even numbers are 20 and 22.

$\rule{300}{1.5}$

$\mathfrak{\large{\underline{\underline{Verification :-}}}}$

Place the value of x and check if both the sides as same or not.

$\longrightarrow$ 2(20) = (20 + 2) + 18

$\longrightarrow$ 40 = 22 + 18

$\longrightarrow$ 40 = 40

$\longrightarrow$ LHS = RHS

Both sides are same.

$\therefore$ The Consecutive Even numbers are 20 and 22.