Find two consecutive even integers such that twice the smaller exceeds the larger by 18.
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Answered by
8
Answer:
22 and 20 are the two even consecutive numbers.
Step-by-step explanation:Twice of the Smaller number exceeds the larger is by 18
2x = (x + 2) + 18
2x = x + 2 + 18
2x = x + 20
2x - x = 20
x = 20
Smaller number = 20
Value of (x + 2)
20 + 2
22
Larger number = 22
Therefore 22 and 20 are the two even consecutive numbers.
Answered by
3
Answer:
therefore 20and22
Step-by-step explanation:
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