Math, asked by juleesingh633, 2 months ago

Find two consecutive even integers such that twice the smaller exceeds the larger by 18.














Answers

Answered by nivedhamohanbabu2205
8

Answer:

22 and 20 are the two even consecutive numbers.

Step-by-step explanation:Twice of the Smaller number exceeds the larger is by 18

  2x = (x + 2) + 18

2x = x + 2 + 18

2x = x + 20

2x - x = 20

x = 20

Smaller number = 20

Value of (x + 2)

20 + 2

 22

Larger number = 22

Therefore 22 and 20 are the two even consecutive numbers.

Answered by singhshila722
3

Answer:

therefore 20and22

Step-by-step explanation:

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