Question

find two consecutive even integers such that two - fifth of the smaller exceeds two - eleventh of the larger number by 4 ......
pls give an explanation.......
best explaned and the correct answer will be marked as the brainliest.......​

Answer 1

Answer:

40

Step-by-step explanation:

Let x & x+2 be the 2 consecutive even integers.

2x=(x+2)+18

2x=x+20

2x-x=20

x=20 answer.

for the smallest integer.

20+2=22 answer.

for the larger integer.

Proof:

2*20=22+18

40=40

Answer 2

Answer:

2/5 x = 2/11 y +4

x=y-1

2/5 (y-1) = 2/11 y +4

2/5 y -2/5 = 2/11 y +4

2/5 y -2/11 y = 4+ 2/5

(22y-10y) /55 = (20+2) /5

12y/55=22/5

y= 22×55/(5×12)

y=20.16

x=19.16