Question

find two consecutive even integers such that two-fifth of the small exceeds two-eleventh of the larger by 4
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answer with all steps
fast please​

Answer 1

Answer: The Numbers are 20 and 22

Step-by-step explanation:

Let the Numbers Be x & (x+2)

Given,

2x/5=2(x+2)/11 + 4

=>2x = 5[2x+4+44]/11

=>22x=5[2x+48]

=>22x = 10x + 240

=>22x-10x = 240

=>12x = 240

=>x=20

Since;

x=20

Therefore;

(x+2)=>20+2=22