Find two consecutive even no. such that the smaller no. is 8/9 times the larger no.
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Answered by
1
numbers = x and x +2
x = (x+2) x 8/9
x = 8x/9 + 16/9
(9x - 8x)/9 = 16/9
x = 16
x + 2 = 16 + 2 =18
consecutive numbers = 16 and 18
Answered by
2
❤❤Here is your answer ✌ ✌
Let's number be X and (x+2)
According to question
x= (x+2)×8/9
x=8x/9+16/9
(9x-8x)/9=16/9
x=16✔
=x+2
=16+2=18✔✔
Let's number be X and (x+2)
According to question
x= (x+2)×8/9
x=8x/9+16/9
(9x-8x)/9=16/9
x=16✔
=x+2
=16+2=18✔✔
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