Question

find two consecutive even number such that two-five of smaller exceeds one-forth of the greatest by 1.

Answer 1

Step-by-step explanation:

let the two consecutive even no. be x and (x+2)

A/Q

$= > \frac{2}{5} x - \frac{1}{4} (x + 2) = 1 \\ = > \frac{8x - 5x - 10}{20} = 1 \\ = > 3x - 10 = 20 \\ = > 3x = 30 \\ = > x = 10$

therefore the required no. are 10 and 12