find two consecutive even number whose sum of the sqaure is 1060
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Hey mate !!
Here's the answer !!
Let the two consecutive even numbers be " x " and " x + 2 "
Given - Sum of squares of two consecutive even numbers is equal to 1060.
=> ( x )² + ( x + 2 )² = 1060
= x² + ( x² + 4x + 4 ) = 1060
= x² + x² + 4x + 4 = 1060
= 2x² + 4x + 4 - 1060 = 0
= 2x² + 4x -1056 = 0
Divide by 2 throughout the equation
= x² + 2x - 528 = 0
= x² + 24x - 22x - 528 = 0
= x ( x + 24 ) - 22 ( x + 24 ) = 0
= ( x + 24 ) ( x - 22 ) = 0
=> x = 22 , - 24
Both the numbers are possible as when they are squared they become positive.
Hence if x = 22, the numbers are 22 and 24.
If x = - 24, then the numbers are - 24 and - 22.
Hope my answer helped you !!
Cheers !!
Here's the answer !!
Let the two consecutive even numbers be " x " and " x + 2 "
Given - Sum of squares of two consecutive even numbers is equal to 1060.
=> ( x )² + ( x + 2 )² = 1060
= x² + ( x² + 4x + 4 ) = 1060
= x² + x² + 4x + 4 = 1060
= 2x² + 4x + 4 - 1060 = 0
= 2x² + 4x -1056 = 0
Divide by 2 throughout the equation
= x² + 2x - 528 = 0
= x² + 24x - 22x - 528 = 0
= x ( x + 24 ) - 22 ( x + 24 ) = 0
= ( x + 24 ) ( x - 22 ) = 0
=> x = 22 , - 24
Both the numbers are possible as when they are squared they become positive.
Hence if x = 22, the numbers are 22 and 24.
If x = - 24, then the numbers are - 24 and - 22.
Hope my answer helped you !!
Cheers !!
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