Question

Find two consecutive even numbers such that seven times the first exceeds five times the second by ♡ 54. (1)30 &32 (2)30&34 (3)34&36 (4)32&43

Answer 1

Answer:

32 and 34.

Step-by-step explanation:

Let the numbers be x and x+2.

According to problem

7x = 5(x+2)+54

7x = 5x+10+54

7x-5x = 64

2x = 64

x = 32

Thus the numbers are 32 and 34.

P.S. You marked final option wrong.