Question

Find two consecutive even numbers such that smaller of the two number is 8/9 times of the larger number

Answer 1

Answer: 16, 18

Step-by-step explanation: let the two consecutive even numbers be x and x+2

A/Q,

x = 8/9 (x+2)

=> 9x = 8x + 16

=> 9x - 8x = 16

=> x = 16

Therefore, smaller no. is 16 and larger no. is 16+2 = 18