Question

Find two consecutive even numbers that tow fifth of the smaller exceeds one fourth of the greater by 1​

Answer 1

Answer:

10 and 12

Step-by-step explanation:

Let the smaller number be x

Then the second number will be x+2 (as each consecutive even numbers will differ by 2)

It is given that 2/5th of x exceeds 1/4th of (x+2) by 1

⇒2x/5-1/4 (x+2)=1

⇒2x/5-(x+2)/4=1

⇒(4×2x-5(x+2))/20=1

⇒8x-5x-10=20

⇒3x-10=20

⇒3x=20+10=30

⇒x=30/3=10

So the numbers are 10 and 12