Find two consecutive even numbers whose product is 288?
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let two consecutive even number be x and x+2 respectively.
a/q
X(x+2)=288
x^2+2x-288=0
X=-2+√(2^2-4×1×-288)/2×1
X=(-2+√1156)/2
X=-2+34/2
X=16
hence two consecutive even number are 16 and 16+2=18 respectively.
a/q
X(x+2)=288
x^2+2x-288=0
X=-2+√(2^2-4×1×-288)/2×1
X=(-2+√1156)/2
X=-2+34/2
X=16
hence two consecutive even number are 16 and 16+2=18 respectively.
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