Question

Find two consecutive even positive integer's such that their product is 1520

Answer 1

Answer:

38 and 40

Step-by-step explanation:

n(n + 2) = 1520

n² + 2n = 1520

n² + 2n - 1520 = 0

$n_{1}$ = 38

$n_{2}$ = - 40 (NOT a solution for the task)

The numbers are 38 and 40.