Math, asked by mina2006, 11 months ago

find two consecutive even +'ve integer.sum of whose square is 100​

Answers

Answered by Anonymous
1

Let the two positive even intergers be

x and x+2

Acco. to the given condition

x {}^{2}  + (x + 2) {}^{2}  = 100 \\ x {}^{2}  +  {x}^{2}  + 4 + 4x = 100 \\ 2 {x}^{2}  + 4x + 4 = 100

Answered by nishitadeka82
2

heya mate....

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Answer:------

Let the two positive even intergers be

Let the two positive even intergers bex and x+2

Let the two positive even intergers bex and x+2Acco. to the given condition

Let the two positive even intergers bex and x+2Acco. to the given condition\begin{lgathered}x {}^{2} + (x + 2) {}^{2} = 100 \\ x {}^{2} + {x}^{2} + 4 + 4x = 100 \\ 2 {x}^{2} + 4x + 4 = 100\end{lgathered}

Let the two positive even intergers bex and x+2Acco. to the given condition\begin{lgathered}x {}^{2} + (x + 2) {}^{2} = 100 \\ x {}^{2} + {x}^{2} + 4 + 4x = 100 \\ 2 {x}^{2} + 4x + 4 = 100\end{lgathered} x

Let the two positive even intergers bex and x+2Acco. to the given condition\begin{lgathered}x {}^{2} + (x + 2) {}^{2} = 100 \\ x {}^{2} + {x}^{2} + 4 + 4x = 100 \\ 2 {x}^{2} + 4x + 4 = 100\end{lgathered} x 2

Let the two positive even intergers bex and x+2Acco. to the given condition\begin{lgathered}x {}^{2} + (x + 2) {}^{2} = 100 \\ x {}^{2} + {x}^{2} + 4 + 4x = 100 \\ 2 {x}^{2} + 4x + 4 = 100\end{lgathered} x 2 +(x+2)

Let the two positive even intergers bex and x+2Acco. to the given condition\begin{lgathered}x {}^{2} + (x + 2) {}^{2} = 100 \\ x {}^{2} + {x}^{2} + 4 + 4x = 100 \\ 2 {x}^{2} + 4x + 4 = 100\end{lgathered} x 2 +(x+2) 2

Let the two positive even intergers bex and x+2Acco. to the given condition\begin{lgathered}x {}^{2} + (x + 2) {}^{2} = 100 \\ x {}^{2} + {x}^{2} + 4 + 4x = 100 \\ 2 {x}^{2} + 4x + 4 = 100\end{lgathered} x 2 +(x+2) 2 =100

Let the two positive even intergers bex and x+2Acco. to the given condition\begin{lgathered}x {}^{2} + (x + 2) {}^{2} = 100 \\ x {}^{2} + {x}^{2} + 4 + 4x = 100 \\ 2 {x}^{2} + 4x + 4 = 100\end{lgathered} x 2 +(x+2) 2 =100x

Let the two positive even intergers bex and x+2Acco. to the given condition\begin{lgathered}x {}^{2} + (x + 2) {}^{2} = 100 \\ x {}^{2} + {x}^{2} + 4 + 4x = 100 \\ 2 {x}^{2} + 4x + 4 = 100\end{lgathered} x 2 +(x+2) 2 =100x 2

Let the two positive even intergers bex and x+2Acco. to the given condition\begin{lgathered}x {}^{2} + (x + 2) {}^{2} = 100 \\ x {}^{2} + {x}^{2} + 4 + 4x = 100 \\ 2 {x}^{2} + 4x + 4 = 100\end{lgathered} x 2 +(x+2) 2 =100x 2 +x

Let the two positive even intergers bex and x+2Acco. to the given condition\begin{lgathered}x {}^{2} + (x + 2) {}^{2} = 100 \\ x {}^{2} + {x}^{2} + 4 + 4x = 100 \\ 2 {x}^{2} + 4x + 4 = 100\end{lgathered} x 2 +(x+2) 2 =100x 2 +x 2

Let the two positive even intergers bex and x+2Acco. to the given condition\begin{lgathered}x {}^{2} + (x + 2) {}^{2} = 100 \\ x {}^{2} + {x}^{2} + 4 + 4x = 100 \\ 2 {x}^{2} + 4x + 4 = 100\end{lgathered} x 2 +(x+2) 2 =100x 2 +x 2 +4+4x=100

Let the two positive even intergers bex and x+2Acco. to the given condition\begin{lgathered}x {}^{2} + (x + 2) {}^{2} = 100 \\ x {}^{2} + {x}^{2} + 4 + 4x = 100 \\ 2 {x}^{2} + 4x + 4 = 100\end{lgathered} x 2 +(x+2) 2 =100x 2 +x 2 +4+4x=1002x

Let the two positive even intergers bex and x+2Acco. to the given condition\begin{lgathered}x {}^{2} + (x + 2) {}^{2} = 100 \\ x {}^{2} + {x}^{2} + 4 + 4x = 100 \\ 2 {x}^{2} + 4x + 4 = 100\end{lgathered} x 2 +(x+2) 2 =100x 2 +x 2 +4+4x=1002x 2

Let the two positive even intergers bex and x+2Acco. to the given condition\begin{lgathered}x {}^{2} + (x + 2) {}^{2} = 100 \\ x {}^{2} + {x}^{2} + 4 + 4x = 100 \\ 2 {x}^{2} + 4x + 4 = 100\end{lgathered} x 2 +(x+2) 2 =100x 2 +x 2 +4+4x=1002x 2 +4x+4=100

Let the two positive even intergers bex and x+2Acco. to the given condition\begin{lgathered}x {}^{2} + (x + 2) {}^{2} = 100 \\ x {}^{2} + {x}^{2} + 4 + 4x = 100 \\ 2 {x}^{2} + 4x + 4 = 100\end{lgathered} x 2 +(x+2) 2 =100x 2 +x 2 +4+4x=1002x 2 +4x+4=100

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hope it helps uh

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