find
two consecutive
integer, A sum of whose square
is 365
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1
Answer:
Step-by-step explanation:
Let the two integers be x and x+1
x² + (x + 1)² = 365
x² + x² + 2x + 1 = 365
2x² + 2x - 364 = 0
=> x² + x - 182 = 0
=>x² + 14x - 13x - 182 = 0
=> x (x + 14) - 13(x + 14) = 0
=> (x - 13)(x+14) = 0
=> x = 13 or -14
Thus the consecutive integers are 13,14 and -14, -13.
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