Question

Find two consecutive integers such that the product of 155 is greater than their sum.

Answer 1

HEY MATE YOUR ANSWER IS HERE...

★ACCORDING TO THE QUESTION★

LET THE CONSECUTIVE INTEGERS BE

X and X +1

HENCE ,

$(x )( x + 1) = (x) + (x + 1) + 155 \\ \\ (x)(x + 1) - (x) - (x + 1) = 155 \\ \\ {x}^{2} + x -2 x - 1 = 155 \\ \\ {x}^{2} - x - 1 = 155$

${x}^{2} - x = 155 \\ \\ {x}^{2} - x - 155 = 0$

NOW BY MIDDLE TERM SPLIT

${x}^{2} - 13x + 12x - 155 = 0$

$x(x - 13) + 12(x - 13) = 0$

$(x - 13)(x + 12) = 0$

HENCE VALUE OF “ X ”

$x = 13 \: \: and \: x = - 12$

CONSECUTIVE NUMBERS IF

VALUE OF “ X ” = 13

13 AND 14

and

CONSECUTIVE NUMBERS IF

CONSECUTIVE NUMBERS IF VALUE OF “ X ” = - 12

-12 AND -11

THANKS FOR UR QUESTION HOPE IT HELPS

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