Question

find two consecutive integers whose product is 42​

Answer 1

Answer:

integers are 6 and 7

Step-by-step explanation:

let the integers be n and n+1

n×n+1=42

n^2+n=42

n^2+n-42=0

solve this to get the ans

Answer 2

Answer:

6 , 7

Step-by-step explanation:

( x ) ( x + 1 ) = 42

x² + x = 42

x² + x - 42 = 0

x² + 7x - 6x - 42 = 0

x ( x + 7 ) - 6 ( x + 7 ) = 0

( x - 6 ) ( x + 7 ) = 0

x = -6 or 7

consequetive integers are, 6 and 7