find two consecutive integers whose sum is 25
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Let the required numbers be x and x+1.
Given: x2 + (x+1)2 = 25
2x2 + 2x - 24 = 0
Þ x2 + x - 12 = 0
i.e. x2 + 4x - 3x - 12 = 0
i.e. x(x + 4) - 3(x + 4) = 0
(x + 4) (x - 3) = 0
x = - 4 or x = 3
Rejecting x = -4, we get the given consecutive positive integers as
x = 3 and x + 1 = 3 + 1 = 4
thanks!
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3
Answer:
the answer is 16,9.
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