Question

Find two consecutive multiples of 3 whose product is 270.

Answer 1

Let the two multiples be x, x +3
[ they are consecutive multiples, consecutive multiples of n differ by n ]

So

x(x+3)=270

x²+3x-270=0

x²+18x-15x-270=0

x(x+18)-15(x+18)=0

(x-15)(x+18)=0

x=15
considering numbers are positive

There four numbers are 15,15+3=15,18

Answer 2

Answer:

Step-by-step explanation:

Let x and x+3 be the consecutive multiples of 3, it is given that the product of two consecutive multiples of 3 is equal to=270

⇒$x(x+3)=270$

⇒$x^{2}+3x-270=0$

⇒$x^{2}+18x-15x-270=0$

⇒$x(x+18)-15(x+18)=0$

⇒$(x-15)(x+18)=0$

Considering the positive values, x=15, then x+3=15+3=18

Hence, two consecutive multiples of 3 are 15 and 18.