Find two consecutive natural numbers the sum of whose square is 145
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Answer:
Step-by-step explanation:
Let the two numbers be x and x+1
Given:sum of the two numbers square is 145
=>X^2+(x+1)^2=145
x^2+x^2+2x+1=145
2x^2+2x+1-145=0
2x^2+2x-144=0
Now, divide all terms by 2
=>x^2+x-72=0
factor (9*8=72)
( x+9)(x-8)=0
x+9=0
x=-9 and x+1=-8, -8 and -9
x-8=0
x=8 and x+1=9, 8 and 9
We have 2 solutions
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abhijithappu:
kkkk but instead of using sum and product method we used quadratic equation formula y don't we get the ans
Yes you can use.
but i didn't get the ans
can y plz do it
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