Question

Find two consecutive natural numbers whose product is 20 in quadratic equation

Answer 1

Let one no. be x and other be x+1

As the are consecutive no.

ATQ

(x)(x+1) = 20

x²+x = 20

x² + x - 20 =0

x²+5x - 4x - 20 = 0

x(x +5)-4(x +5) = 0

(x - 4)(x+5)=0

If x-4 =0

x =4

Or x+5 =0

x = -5

But it is rejected as natural no. Can't be negative

Thus the no. is 4 and other no. Is x+1 =(4+1 )=5hop

_____________________________♦️ ♦️ ♦️

Hope it helps!!! ☺️

Keep calm and study hard

☘ℙ☘