Question

Find two consecutive natural numbers whose sum is 203

Answer 1

$let \: no \: be \: x \: and \: x + 1 \\ x + (x + 1) = 203 \\ 2x + 1 = 203 \\ 2x = 202 \\ x = 101 \\ x + 1 = 102$

Answer 2

Answer:

let no be = x

X=(x+1)=203

2x +1=203

=2x=202

x=101

x+1=102

Step-by-step explanation:

I I think this will help you