Question

Find two consecutive numbers such that 4/5 of the smaller number exceeds half of the larger number by 1

Answer 1

Let the number be X and X+1
4x/5 - (x+1)/2 =1
8x - 5x-5 = 10
3x =15
X =5
Numbers are 5 &6

Answer 2

let 1 no be 2x, secnd is 2x+2

2/5*2x=2x+2* 1/4 +1

4x = x+1 + 1

 5        2

 

8x-5x-5 = 1  =>  3x - 5= 10 => 3x = 15 => x= 5
10


thus, first no = 2x= 10

2nd no = 2x+2 = 12