Question

Find two consecutive numbers such that one-third of the greater exceeds one-fourth of the lesser by 5.​

Answer 1

Answer:

Let nos. Be ( x), ( x + 1)

( x + 1)/ 3 - x/4 = 5

x + 4 = 60

x = 56

x + 1 = 57

• Two consecutive numbers are 56 & 57.