Question

find two consecutive numbers such that the greater number added to 3 times
the smaller number makes a total of 53.​

Answer 1

Step-by-step explanation:

2nd no- x+1 (greater no )

x+1 + 3( x) =53

x+1+3x=53

4x+1=53

4x=53-1

4x=52

x=13

therefore,one no is 13 &other is 14

Answer 2

Answer:

Step-by-step explanation:

Two consecutive numbers are pairs of numbers like

1,2

or

18,19

one right after the other". That is, one of the integers is immediately to the right of the other, when viewed on a number line.

Denote the smaller integer using

Then the larger of the two consecutiveintegers must be

n+1

n+1

. That leaves us with solving the following:

n+(n+1)=2n+1=53.

n+(n+1)=2n+1=53.

That means

2n=53−1=52,

2n=53−1=52,

so

n=

52

2

=26

n=522=26

So, we have

n=26,n+1=27,

n=26,n+1=27,

as desired.

answered

Aug 10 '14 at 14:34

1

x+(x+1)=532x+1=53

2x=52x=26

x+(x+1)=532x+1=532x=52x=26

The numbers are:

x=26

x=26

and

x+1=27

Hope it helps u

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